题目描述
查找当前薪水(to_date='9999-01-01')排名第二多的员工编号emp_no、薪水salary、last_name以及first_name,不准使用order by CREATE TABLE `employees` ( `emp_no` int(11) NOT NULL, `birth_date` date NOT NULL, `first_name` varchar(14) NOT NULL, `last_name` varchar(16) NOT NULL, `gender` char(1) NOT NULL, `hire_date` date NOT NULL, PRIMARY KEY (`emp_no`)); CREATE TABLE `salaries` ( `emp_no` int(11) NOT NULL, `salary` int(11) NOT NULL, `from_date` date NOT NULL, `to_date` date NOT NULL, PRIMARY KEY (`emp_no`,`from_date`));
输入描述:
无
输出描述:
emp_no | salary | last_name | first_name |
---|---|---|---|
10009 | 94409 | Peac | Sumant |
1 select e.emp_no, max(s.salary) , e.last_name, e.first_name 2 from employees e, salaries s 3 where s.to_date = '9999-01-01' and e.emp_no = s.emp_no and s.salary <> 4 (select max(salary)5 from employees e, salaries s 6 where s.to_date = '9999-01-01' and e.emp_no = s.emp_no)